Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated June 22nd, 2023


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Problem: Solve for the variable. Check a value if it is extraneous.
 
r + 5  = r - 1
 
r + 5 = ( r + )2
 
r + 5 = r2 + r +
 
0 = r2 + r +
 
0 = ( r + )( r + )
 
r1 =     r2 =
extraneous   extraneous