Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated June 22nd, 2023

Status: Waiting for your answers.





Problem: Solve for the variable. Check a value if it is extraneous.
 
√ e + 23  = e + 11
 
e + 23 = ( e + )2
 
e + 23 = e2 + e +
 
0 = e2 + e +
 
0 = ( e + )( e + )
 
e1 =     e2 =
extraneous   extraneous