Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated June 22nd, 2023

Status: Waiting for your answers.





Problem: Solve for the variable. Check a value if it is extraneous.
 
√ p + 15  = p + 3
 
p + 15 = ( p + )2
 
p + 15 = p2 + p +
 
0 = p2 + p +
 
0 = ( p + )( p + )
 
p1 =     p2 =
extraneous   extraneous